The equation below can be used to find the specific heat capacity of a substance. work out the specific heat capacity of a substance if it takes 5,200j of energy to heat 2kg of it from 42°c to 47°c.
The Equation Below Can Be Used To Find The Specific Heat Capacity Of A Substance. Work Out The Specific Heat Capacity Of A Substance If It Takes 5,200J Of Energy To Heat 2Kg Of It From 42°C To 47°C.
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The Equation Below Can Be Used To Find The Specific Heat Capacity Of A Substance. Work Out The Specific Heat Capacity Of A Substance If It Takes 5,200J Of Energy To Heat 2Kg Of It From 42°C To 47°C.. Given that it takes 1,000 j to heat 25 g of a substance by 100°c, we can calculate its specific heat capacity using the formula q = mcδt, where q is the heat energy, m is the. Find the specific heat capacity of a substance that takes 5,200j of energy to heat 2kg of it from 42°c to 47°c.
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See the formula, the given values, the calculation steps and the answer. Work out the specific heat capacity of a substance if it takes 5,200j of energy to heat 2kg of it from 42°c to 47°c. Learn how to calculate the specific heat capacity of a substance using the formula c = e / (m × θ) with an example problem.
Specific Heat Is Also Known As Specific Heat Capacity.
Enter vour answer as a number 1/ka°c. Learn how to calculate the specific heat capacity of a substance using the formula c = e / (m × θ) with an example problem. Work out the specific heat capacity of a substance if it takes 5,200j of energy to heat 2kg of it from 42°c to 47°c.
The Following Equation Describes This Energy Addition:
You can determine the above equation from the units of capacity (energy/temperature). Find the specific heat capacity of a substance that takes 5,200j of energy to heat 2kg of it from 42°c to 47°c. See the steps, units, and highlights of the solution provided by.
See The Formula, The Given Values, The Calculation Steps And The Answer.
Given that it takes 1,000 j to heat 25 g of a substance by 100°c, we can calculate its specific heat capacity using the formula q = mcδt, where q is the heat energy, m is the. That is if a constant has units, the variables must fit together in an equation that results in the. We can solve for c in the q =.