In Δjkl, K = 6.1 Cm, Mm∠K=100° And Mm∠L=29°. Find The Length Of J, To The Nearest 10Th Of A Centimeter.

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In Δjkl, K = 6.1 Cm, Mm∠K=100° And Mm∠L=29°. Find The Length Of J, To The Nearest 10Th Of A Centimeter.. This is a straight application of the law of cosine: Round to the nearest tenth of a centimeter.

Example 3 Construct XYZ if it is given that XY = 6 cm, ZXY = 30
Example 3 Construct XYZ if it is given that XY = 6 cm, ZXY = 30 from www.teachoo.com

### \( \frac{j}{\sin(\angle k)} = \frac{k}{\sin(\angle l)} \). Using the sine rule, the length of side j in triangle δ j k l is calculated to be approximately 4.8 cm. With our given measures, we have ∠k =.

In Triangle Jkl, Given Information:


By sine rule , 4.8 is the length of j, to the nearest 10th of a centimeter. You make the substitutions and do the. Applying this law to what's given, gives us:

We Are Given K = 6.1 Cm, M∠K = 100°, And We Found M∠J = 51°.


Find the length of j, to the nearest 10th of an inch. The calculation involved finding the missing angle and applying the ratio. In order to calculate the unknown values you must enter 3 known values.

Uses The Law Of Sines To Calculate Unknown Angles Or Sides Of A Triangle.


We can use the law of sines to find j: What does the sine rule formula mean? 1 c m, m k = 1 0 0 ° and m l = 2 9 °.

First, Find The Measure Of Angle $$J$$J By Subtracting The Measures Of Angles $$K$$K And $$L$$L From $$180^\Circ$$180∘.


This is a straight application of the law of cosine: Round to the nearest tenth of a centimeter. In j k l, k = 6.

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With our given measures, we have ∠k =. Apply the law of cosines using the known side $$k$$k and. Using the sine rule, the length of side j in triangle δ j k l is calculated to be approximately 4.8 cm.

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