What Is The Solution Of Startroot X + 2 Endroot Minus 15 = Negative 3? X = 142 X = 232 X = 322 No Solution

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What Is The Solution Of Startroot X + 2 Endroot Minus 15 = Negative 3? X = 142 X = 232 X = 322 No Solution. Solve the equation by following steps: To find the roots factor the function, set each facotor to zero, and solve.

Solved = RootIndex 3 StartRoot x EndRoot. y = negative (0.4) RootIndex
Solved = RootIndex 3 StartRoot x EndRoot. y = negative (0.4) RootIndex from www.gauthmath.com

A root is a value for which the function equals zero. Now undo the square, by squaring both sides; By solving the equation x+2 −15 = −3, we find that the solution is x= 142.

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A root is a value for which the function equals zero. \ ( (\sqrt {x+2})^2 = 12^2\) 4. The solutions are the roots of the function.

Square Both Sides To Eliminate The Square Root:


By solving the equation x+2 −15 = −3, we find that the solution is x= 142. For better understanding, consider similar square root. X + 2 = 12^ {2} x+2=122 rearrange unknown terms to the left side of the equation:

Solve The Equation By Following Steps:


There are 3 steps to solve this one. Move the constant to the right side: Therefore, the correct answer is option a.

Now Undo The Square, By Squaring Both Sides;


Not the question you’re looking for? To find the roots factor the function, set each facotor to zero, and solve. \ (\sqrt {x+2} = 12\) 3.

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