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The Sum Of A Number And Its Square Is 42. Which Equation Can Be Used To Find The Two Numbers For Which This Is True? X2 + X = 42 X2 + 2X = 42 X2 + X + 42 = 0 X2 + 2X + 42 = 0. \ ( x^ {2} + x = 42 \). X2 + x = 42 x2 + 2x = 42 x2 + x + 42 = 0 x2
This equation represents the sum of x and its square being equal to 42. The equation that represents the sum of a number and its square equaling 42 is x2 + x = 42. Therefore, option a is the correct choice.
X2 + x = 42 x2 + 2x = 42 x2 + x + 42 = 0 x2 This corresponds directly with option a. Therefore, the equation that can be used is:
The equation that represents the sum of a number and its square equaling 42 is x2 + x = 42. Let x = the number then, x + x2 = 42. Find the number(s) that satisfy the equation x+x2=42.
Given that this sum is $$42$$42, the equation is $$x + x^ {2} = 42$$x +x2 = 42. The equation that best describes the problem is x2 + x = 42. Watch a video answer and see similar questions with solutions.
This equation represents the sum of x and its square being equal to 42. Which equation can be used to find the two numbers for which this is true? \ ( x^ {2} + x = 42 \).
Therefore, option a is the correct choice. The goal here is finding possible values of x. The problem states that the sum of a number (x) and its square (x²) is 42, which translates directly into the equation x² + x = 42.
