The lengths of a lawn mower part are approximately normally distributed with a given mean mu = 4 in. and standard deviation sigma = 0.2 in. what percentage of the parts will have lengths between 3.8 in. and 4.2 in.? 34% 68% 95% 99.7%
The Lengths Of A Lawn Mower Part Are Approximately Normally Distributed With A Given Mean Mu = 4 In. And Standard Deviation Sigma = 0.2 In. What Percentage Of The Parts Will Have Lengths Between 3.8 In. And 4.2 In.? 34% 68% 95% 99.7%
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The Lengths Of A Lawn Mower Part Are Approximately Normally Distributed With A Given Mean Mu = 4 In. And Standard Deviation Sigma = 0.2 In. What Percentage Of The Parts Will Have Lengths Between 3.8 In. And 4.2 In.? 34% 68% 95% 99.7%. The percentage of lawn mower parts that will have lengths between 3.8 in. See the solution, steps and answer on gauthmath, a math learning platform.
Solved Use the given statistics to complete parts (a) and from www.chegg.com
We know that the distribution is normal with mean mu = 4 in. What percentage of the parts will have lengths between 3.8 in. And standard deviation sigma = 0.2 in.step 2/82.
Find Out How To Solve A Problem Involving The Lengths Of A Lawn Mower Part That Are Normally Distributed With Mean 4 In.
What percentage of the parts will have lengths between 3.8 in. See the solution, steps and answer on gauthmath, a math learning platform. And standard deviation 0.2 in.
We Know That The Distribution Is Normal With Mean Mu = 4 In.
We want to find the percentage of parts that have lengths between 3.8 in. Find out how to calculate the percentage of lawn mower parts with lengths between 3.8 in. The percentage of lawn mower parts that will have lengths between 3.8 in.
Using The Normal Distribution Formula.
And standard = 0.2 in. Find the percentage of lawn mower parts with lengths between 3.8 in. Can be determined by calculating the area under the normal distribution curve within this range.
The Lengths Of A Lawn Mower Part Are Approximately Normally Distributed With A Given Mean Μ = 4 In.