Reyna Has 5 Coins Worth 10 Cents Each And 4 Coins Worth 25 Cents Each. If She Chooses Two Of These Coins At Random, What Is The Probability That The Two Coins Combined Will Be Worth At Least 35 Cents?

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Reyna Has 5 Coins Worth 10 Cents Each And 4 Coins Worth 25 Cents Each. If She Chooses Two Of These Coins At Random, What Is The Probability That The Two Coins Combined Will Be Worth At Least 35 Cents?. 5 coins worth 10 cents each. If she chooses two of these coins at random, what is the probability that the two coins together will be worth at least.

SOLUTION reyna has 5 coins worth 10 cents each and 4 coins worth 25
SOLUTION reyna has 5 coins worth 10 cents each and 4 coins worth 25 from www.algebra.com

Total coins = 5 + 4 = 9 coins. She has 4 coins worth 25 cents each. Reyna has 5 coins worth 10 cents each and 4 coins worth 25 cents each.

We Will First Determine The Total Number Of Ways She Can.


Reyna has 5 coins worth 10 cents each and 4 coins worth 25 cents each. To solve this question, we need to calculate the probability that reyna will pick two coins that together are worth at least 35 cents. To solve this problem, let's consider the possible.

If She Chooses Two Of These Coins At Random, What Is The Probability That The Two Coins Together Will Be Worth At Least.


That could be 1 ten cent coin and 1 twenty five cent coin,. Total coins = 5 + 4 = 9 coins. Reyna has 5 coins worth 10 cents each.

Reyna Has 5 Coins Worth 10 Cents Each And 4 Coins Worth 25 Cents Each.


We need to find the number of ways to choose 2 coins such that their total value is at least 35 cents. Let's go through the steps to find this probability: She has 4 coins worth 25 cents each.

5 Coins Worth 10 Cents Each.


5 coins are each worth 10 cents. The probability that the two coins chosen together will be worth at least 35 cents is approximately 0.7222, or 13/18. 4 coins are each worth 25 cents.

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4 coins worth 25 cents each. She would need to pick two coins that are worth at least 35 cents.

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