Particle Q1 Has A Charge Of 2.7 Μc And A Velocity Of 773 M/S. If It Experiences A Magnetic Force Of 5.75 × 10–3 N, What Is The Strength Of The Magnetic Field? T

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Particle Q1 Has A Charge Of 2.7 Μc And A Velocity Of 773 M/S. If It Experiences A Magnetic Force Of 5.75 × 10–3 N, What Is The Strength Of The Magnetic Field? T. The strength of the magnetic field experienced by particle q₁ is 2.8 t (c), and the magnetic force on particle q₂ is 0.042 n (a). Particle q1 has a charge of 2.7 μc and a velocity of 773 m/s.

Field and Force Assignment Particle q 1 has a charge of 2 μC
Field and Force Assignment Particle q 1 has a charge of 2 μC from www.studocu.com

Where f is the magnetic force, q1 is the charge of the particle, v is the velocity, and b is the strength of the magnetic field. We can rearrange the formula to solve for. B = f / (q1 * v).

Particle Q1 Has A Charge Of 2.7 Μc And A Velocity Of 773 M/S.


We can rearrange the formula to solve for. Where f is the magnetic force, q1 is the charge of the particle, v is the velocity, and b is the strength of the magnetic field. According to physic's magnetic law, the relation between a magnetic force, velocity, charge and magnetic field of a particle is :[tex]f_{b} =|q|vbsin\alpha[/tex];

If It Experiences A Magnetic Force.


Frac 2 _ t the same magnetic field, particle q_2 has a charge of 2.0 μc and a velocity of 1.21*. 【solved】click here to get an answer to your question : Where f is the magnetic force, q1 is the charge of the particle, v is the velocity, and b is the strength of the magnetic field.

Rearranging The Formula To Solve For B, We Have:


The strength of the magnetic field experienced by particle q₁ is 2.8 t (c), and the magnetic force on particle q₂ is 0.042 n (a). Θ is the angle between the velocity and the. Rearranging the formula to solve for b, we have:

B = F / (Q1 * V).


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