Mrs. Culland Is Finding The Center Of A Circle Whose Equation Is X2 + Y2 + 6X + 4Y – 3 = 0 By Completing The Square. Her Work Is Shown. X2 + Y2 + 6X + 4Y – 3 = 0 X2 + 6X + Y2 + 4Y – 3 = 0 (X2 + 6X) + (Y2 + 4Y) = 3 (X2 + 6X + 9) + (Y2 + 4Y + 4) = 3 + 9 + 4 Which Completes The Work Correctly? (X – 3)2 + (Y – 2)2 = 42, So The Center Is (3, 2). (X + 3)2 + (Y + 2)2 = 42, So The Center Is (3, 2). (X – 3)2 + (Y – 2)2 = 42, So The Center Is (–3, –2). (X + 3)2 + (Y + 2)2 = 42, So The Center Is (–3, –2).. Click here 👆 to get an answer to your question ️ mrs. Find the equation of the circle passing through the point of intersection of the lines x + 3y = 0 and 2x − 7y = 0 and whose centre is the point of intersection of the lines x + y + 1 = 0 and x − 2y +.

Culland is finding the center of a circle whose which completes the work correctly? Click here 👆 to get an answer to your question ️ mrs. Center of a circle whose.