Log(x2 − 15) = log(2x) form 1 to 5. x2 − 2x − 15 = 0 potential solutions are −3 and 5 x2 − 15 = 2x x − 5 = 0 or x + 3 = 0 (x − 5)(x + 3) = 0
Log(X2 − 15) = Log(2X) Form 1 To 5. X2 − 2X − 15 = 0 Potential Solutions Are −3 And 5 X2 − 15 = 2X X − 5 = 0 Or X + 3 = 0 (X − 5)(X + 3) = 0
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Log(X2 − 15) = Log(2X) Form 1 To 5. X2 − 2X − 15 = 0 Potential Solutions Are −3 And 5 X2 − 15 = 2X X − 5 = 0 Or X + 3 = 0 (X − 5)(X + 3) = 0. The key steps involve removing the logarithms, rearranging the equation into a quadratic form, factoring the quadratic, finding potential solutions, and (implicitly) checking the validity of the. This number is a true solution of the original equation.
Order the steps to solve the equation Log(x^215)=log(2x) form 1 to 5 from brainly.com
Order the steps to solve the equation log(x2 − 15) = log(2x) form 1 to 5. The key steps involve removing the logarithms, rearranging the equation into a quadratic form, factoring the quadratic, finding potential solutions, and (implicitly) checking the validity of the. Order the steps to solve the equationlog (x2 − 15) = log (2x) form 1 to 5.
This Number Is A True Solution Of The Original Equation.
Order the steps to solve the equationlog (x2 − 15) = log (2x) form 1 to 5. Then rearrange it to get a quadratic equation, factor, and find potential solutions, ensuring the arguments for the. Order the steps to solve the equation log(x2 − 15) = log(2x) form 1 to 5.
The Key Steps Involve Removing The Logarithms, Rearranging The Equation Into A Quadratic Form, Factoring The Quadratic, Finding Potential Solutions, And (Implicitly) Checking The Validity Of The.
X2 − 2x − 15 = 0 potential solutions are −3 and 5 x2 − 15 = 2x x − 5 = 0 or x + 3 = 0 (x − 5)(x + 3) = 0 X^{\msquare} \log_{\msquare} \sqrt{\square} \nthroot[\msquare]{\square} \le \ge \frac{\msquare}{\msquare} \cdot \div: To solve the equation log(x2 − 15) = log(2x), first set the arguments equal, rearrange, factor, solve for x, and check solutions.
To Solve Log(X2 − 15) = Log(2X), First Equate The Arguments To Find X2 − 15 = 2X.
