In The Same Magnetic Field, Particle Q2 Has A Charge Of 42.0 Μc And A Velocity Of 1.21 × 103 M/S. What Is The Magnitude Of The Magnetic Force Exerted On Particle 2?

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In The Same Magnetic Field, Particle Q2 Has A Charge Of 42.0 Μc And A Velocity Of 1.21 × 103 M/S. What Is The Magnitude Of The Magnetic Force Exerted On Particle 2?. Particle q1 has a charge of 2.7 μc and a velocity of 773 m/s. What is the magnitude of the magnetic force exerted on particle 2?

SOLVED A small particle with a charge of 4.0 μC moves perpendicularly from www.numerade.com

In the same magnetic field, particle q2 has a charge of 42.0μc and a velocity of 1.21× 103m/s. Attractive force means opposite charges so the sign of q 2. Frac 2 _ t the same magnetic field, particle q_2 has a charge of 2.0 μc and a velocity of 1.21*.

By A Distance Of 0.26 M, And Particle 1 Experiences An Attractive Force Of 3.4 N.

Then, the force particle two feels from it is the lorentz force, $\vec{f_2}=q_{2}\vec{v_2}\times\vec{b}$,. The formula for the force depends on the charge of the particle, and the cross product of the particle's velocity and the magnetic field. What is q 2 (magnitude and sign)?

What Is The Magnitude Of The Magnetic Force Exerted On Particle 2?

The direction of the force vector can be found by. Attractive force means opposite charges so the sign of q 2. Where $\vec{v_1}$ is the velocity of particle 1 and $q_{1}$ is its charge.