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Find The Ratio In Which The Line Segment Joining The Points -3 10 And 6 - 8 Is Divided By -1 6. Let the points be a (−3, 10) , b (6, −8) , c (−1, 6) we need to find. The section formula states that if a line.
To find the ratio in which the line segment joining the points (−3,10) and (6,−8) is divided by the point (−1,6), we can use the section formula. ∴ (6 k − 3 k + 1, − 8 k + 10 k + 1) = (− 1, y) ⇒ 6 k − 3 k + 1 = − 1 and y = − 8 k + 10 k + 1. Coordinate geometry class 10, exercise 7.2, q.no.
In the drawn diagram, we have to find the ratio between both the points a c and c b. Suppose p (−1, y) divides the line segment joining a (−3, 10) and b (6 −8) in the ratio k : Let’s assume that the ratio is k:
1 so, m 1 = k, m 2 = 1, so, the ratio is 2: M₂ is given by the section. To find the ratio in which the line segment joining the points (−3,10) and (6,−8) is divided by the point (−1,6), we can use the section formula.
The coordinates of the point p (x, y) which divides the line segment joining the points a (x₁, y₁) and b (x₂, y₂), internally, in the ratio m₁: Coordinate geometry class 10, exercise 7.2, q.no. The section formula states that if a line.
Let ratio be k :
