Consider The Function Y = Cos(X). Which Change Would Increase The Period By A Factor Of 3?

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Consider The Function Y = Cos(X). Which Change Would Increase The Period By A Factor Of 3?. Not the question you’re looking for? Which change would increase the period by a factor of 3?

What is the period of the parent cosine function, y =cos (x) ? 360
What is the period of the parent cosine function, y =cos (x) ? 360 from www.gauthmath.com

Since 2 π / 3 2π/3 2π/3 is the same as 3 ∗ ( 2 π) / 3 3* (2π)/3. If a increases, then the amplitude increase. Since sine has period 2pi, it would happen when the values differ by a multiple of 2pi.

Understand The Effect Of Multiplying The Argument Of The Cosine Function ### The Period Of The Function Y = \Cos (Kx) Is Given By \Frac {2\Pi} {|K|}.


If a increases, then the amplitude increase. Answer to consider the function y=cos (x). There are 2 steps to solve this one.

The Period Of The Basic Cosine Function, Y = \Cos (X) Y=Cos(X), Is 2\Pi 2Π.


This will change the function to y = cos(31x), increasing the period to 6π. Whenever their h values differ by a multiple of the period of the sine function. Post any question and get expert help quickly.

Y = A Cos (Ωx) Where A Is The Amplitude, Ω Is The Frequency.


Consider the function y = cos (x). Multiplying x x x by 3 3 3 will result in the function y = c o s ( 3 x) y=cos (3x) y=cos(3x) , which has a period of 2 π / 3 2π/3 2π/3. Since 2 π / 3 2π/3 2π/3 is the same as 3 ∗ ( 2 π) / 3 3* (2π)/3.

Which Change Would Increase The Period By A Factor Of 3?


Not the question you’re looking for? And if a decreases, then the amplitude decreases. Since sine has period 2pi, it would happen when the values differ by a multiple of 2pi.

Consider The Function Y = Cos (X).


To increase the period of the function y = cos(x) by a factor of 3, we need to multiply x by 31. To increase this period by a factor of 3, the new period should be 3 \times 2\pi = 6\pi 3×2π=6π.

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