Ac ≅ Ae; ∠Acd ≅ ∠Aed Which Relationships Within The Diagram Are True? Check All That Apply. △Acf ≅ △Aeb Because Of Asa. △Acf ≅ △Aeb Because Of Sas. △Acf ≅ △Aeb Because Of Aas. ∠Cfa ≅ ∠Eba Fc ≅ Be Fc ≅ Ac

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Ac ≅ Ae; ∠Acd ≅ ∠Aed Which Relationships Within The Diagram Are True? Check All That Apply. △Acf ≅ △Aeb Because Of Asa. △Acf ≅ △Aeb Because Of Sas. △Acf ≅ △Aeb Because Of Aas. ∠Cfa ≅ ∠Eba Fc ≅ Be Fc ≅ Ac. The correct answer is (a) acf ≅ aeb because of asa. Which relationships within the diagram are true?

[Solved] 1. In the diagram MP¯∥TR¯, m∠PMN=28∘, and m∠MNP=37∘
[Solved] 1. In the diagram MP¯∥TR¯, m∠PMN=28∘, and m∠MNP=37∘ from www.coursehero.com

(d) ∠cfa ≅ ∠eba (e) fc ≅ be. Therefore, based on the isosceles triangle theorem, ∠acd ≅ ∠adc. Triangle acd is an isosceles triangle based on the definition of isosceles triangle.

B) Acf ≅ Aeb Because Of Sas.


Quadrilateral abcd is a parallelogram (the diagonals of a parallelogram bisect each other); Triangle acd is an isosceles triangle based on the definition of isosceles triangle. In δade ad = ae => ∠ade = ∠aed => ∠adc = ∠aeb in δabc ab = ac => ∠abc = ∠acb => ∠abe = ∠acd in δabe & δacd ab = ac ∠abe = ∠acd ∠aeb = ∠adc => δabe ≅ δacd.

Therefore, The Correct Relationship Is:


Therefore, based on the isosceles triangle theorem, ∠acd ≅ ∠adc. Quadrilateral abcd with diagonals ac and bd that bisect each other, and ∠1 ≅ ∠2 (given); ∠acd ≅ ∠aed, because is.

According To Known Information, Overline Ac≌ Overline Ae, ∠ Acd≌ ∠ Aed And Because It's The Same Angle, ∠ Eab≌ ∠ Caf Because ∠ Acd≌ ∠ Aed, So∠ Acf≌ ∠ Aeb.


Acf ≅ aeb because of ac ≅ ae and ∠acd ≅ ∠aed. ∠caf ≅ ∠eab, given that the angle ac ≅ ae; Which relationships within the diagram are true?

We Are Given That Ac ≅ Ae And ∠Acd ≅ ∠Aed.


C) acf ≅ aeb because of aas. Triangle acf and triangle aeb share a common side, af ≅ ab. A) acf ≅ aeb because of asa.

Click Here 👆 To Get An Answer To Your Question ️ Overline Ac≌ Overline Ae;


∠ acd≌ ∠ aed which relationships within the diagram are true? Additionally, we can determine that ∠cfa is congruent to ∠eba since these angles are. (d) ∠cfa ≅ ∠eba (e) fc ≅ be.

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