A radioactive nuclide has 53 protons and 78 neutrons. which is the symbol of this nuclide? superscript 53 subscript 78 upper i. superscript 78 subscript 53 upper p t. superscript 131 subscript 78 upper p t. superscript 131 subscript 53 upper i.
A Radioactive Nuclide Has 53 Protons And 78 Neutrons. Which Is The Symbol Of This Nuclide? Superscript 53 Subscript 78 Upper I. Superscript 78 Subscript 53 Upper P T. Superscript 131 Subscript 78 Upper P T. Superscript 131 Subscript 53 Upper I.
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A Radioactive Nuclide Has 53 Protons And 78 Neutrons. Which Is The Symbol Of This Nuclide? Superscript 53 Subscript 78 Upper I. Superscript 78 Subscript 53 Upper P T. Superscript 131 Subscript 78 Upper P T. Superscript 131 Subscript 53 Upper I.. First, we need to find the atomic number (z) and the mass number (a) of the nuclide. An atom of this radionuclide contains 15 protons, 15 electrons, and 17.
SOLVED A radioactive nuclide has 53 protons and 78 neutrons. Which is from www.numerade.com
In this case, \ ( a = z + n = 53 + 78 = 131 \). An atom of this radionuclide contains 15 protons, 15 electrons, and 17. A = 53 (protons) + 78.
The Symbol For A Radioactive Nuclide With 53 Protons And 78 Neutrons Is 53 131 I Because 53 Corresponds To The Atomic Number For Iodine, And The Mass Number Is The Sum Of.
Which is the symbol of this nuclide? In this case, \ ( a = z + n = 53 + 78 = 131 \). To represent a nuclide, we use the notation ^ {number of protons}_ {number of neutrons} numberof neutronsnumberof protons in this case, the nuclide has 53 protons and 78.
A Radioactive Nuclide Has 53 Protons And 78 Neutrons.
The mass number (a) of a nuclide is the sum of its number of protons (z) and neutrons (n). Study with quizlet and memorize flashcards containing terms like a radioactive nuclide is used to detect eye tumors. To find the mass number (a), add the number of protons (z) and the number of neutrons.
Consider The Nuclear Equation Below.
None of the given options correctly represent the symbol for the nuclide with 53 protons and 78 neutrons. An atom of this radionuclide contains 15 protons, 15 electrons, and 17. The atomic number is equal to the number of protons, and the mass number is the.
A = 53 (Protons) + 78.
The mass number is then: The nuclide with 53 protons. Which represents a balanced nuclear equation?
First, We Need To Find The Atomic Number (Z) And The Mass Number (A) Of The Nuclide.
In this case, there are 53 protons and 78 neutrons. The correct symbol should be _ {53}^ {131}i 53131i, which is not listed among the.
